How it works
| Rule | Example |
|---|---|
| am × an = am+n | 2² × 2⁴ = 2⁶ |
| am ÷ an = am−n | 5⁷ ÷ 5⁴ = 5³ |
| (am)n = amn | (x⁴)⁴ = x¹⁶ |
| (ab)n = anbn | (2x)⁴ = 16x⁴ |
| a⁰ = 1, a−n = 1/an | x⁻² = 1/x² |
To solve exponential equations, write both sides as powers of the same base and set the exponents equal: 729 = 3⁶, so 32x = 729 means 2x = 6. It helps to know the powers of 2 up to 2¹⁰ = 1024 and the powers of 3 up to 3⁶ = 729.
Exponent laws practice problems with solutions
These problems come from Mathyessy's question bank. Try each one before opening the solution.
Simplify 22 × 24.
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Answer: 64
Same base, so add the exponents: 2² × 2⁴ = 2⁶ = 64.
Simplify (2x4)4. What is the coefficient?
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Answer: 16
Raise each factor to the 4th power: 2⁴ × (x⁴)⁴ = 16x¹⁶. The coefficient is 16.
Simplify x5 × x-2 × x3. Give the exponent of the simplified xn form.
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Answer: 6
Add the exponents: 5 + (−2) + 3 = 6, giving x⁶.
If 32x = 729, what is x?
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Answer: 3
729 = 3⁶, so 2x = 6 and x = 3.
Keep going
Related topics
- Prime factorization
- Units digit and cycles
- Arithmetic sequences and series
- Quadratic formula and discriminant
Related practice sets in the app
All Algebra topics · Contest math practice by topic · MATHCOUNTS practice · AMC 8 practice