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Systems of equations practice

Two unknowns need two equations. Contest problems often reward finding what is asked without solving for each variable.

How it works

Elimination: add or subtract the equations so one variable cancels. From x + y = 8 and x − y = 2, adding gives 2x = 10.

Substitution: solve one equation for a variable and plug it into the other. This is best when one coefficient is already 1.

Look at what is asked. If a problem wants x + y, or y + z, try subtracting whole equations instead of solving for everything. Two key identities:

x² + y² = (x + y)² − 2xy     x² − y² = (x + y)(x − y)

Solving Two-Variable Systems practice problems with solutions

These problems come from Mathyessy's question bank. Try each one before opening the solution.

  1. If x + y = 8 and x − y = 2, what is x?

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    Answer: 5

    Add the equations: 2x = 10, so x = 5 (and y = 3).

  2. If x + y + z = 15 and 2x + y + z = 18, what is y + z?

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    Answer: 12

    Subtract the first equation from the second: x = 3. Then y + z = 15 − 3 = 12. Notice you never need y or z separately.

  3. 8 apples and 9 bananas cost 139 cents; 8 apples and 10 bananas cost 150. What does one banana cost?

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    Answer: 11 cents

    The second purchase is the first plus exactly one more banana, so a banana costs 150 − 139 = 11 cents.

  4. If x + y = 10 and xy = 16, what is x² + y²?

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    Answer: 68

    Use x² + y² = (x + y)² − 2xy = 100 − 32 = 68. (The numbers are 2 and 8: 4 + 64 = 68.)

Practice this in Mathyessy →Free, no account needed. Opens the Solving Two-Variable Systems set with instant feedback.

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